# How do you write y = 4x^2-8x-6 into vertex form?

$y = 4 {x}^{2} - 8 x - 6 = 4 {\left(x - 1\right)}^{2} - 10$.
In general $a {x}^{2} + b x + c = a {\left(x + \frac{b}{2 a}\right)}^{2} + \left(c - {b}^{2} / \left(4 a\right)\right) .$