How do you write #y-5 = -2(x+1)^2# in intercept form?
1 Answer
Jan 19, 2018
Explanation:
#"arrange into standard form "y=ax^2+bx+c ;a!=0#
#y-5=-2x^2-4x-2#
#rArry=-2x^2-4x+3larrcolor(blue)"in standard form"#
#"with "a=-2,b=-4" and "c=3#
#"find the roots (x-intercepts) by equating to zero"#
#rArr-2x^2-4x+3=0#
#"use the "color(blue)"quadratic formula"#
#x=(4+-sqrt(16+24))/-4=(4+-sqrt40)/-4=(4+-2sqrt10)/-4#
#rArrx=-1+-1/2sqrt10#
#y=(x-(-1-1/2sqrt10))(x-(-1+1/2sqrt10))#
#rArry=(x+1+1/2sqrt10)(x+1-1/2sqrt10)#