How do you write #y-5=4(x+2)# in standard form?

1 Answer
Jim G.
Mar 31, 2018

#4x-y=-13#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"rearrange "y-5=4(x+2)" into this form"#

#rArry-5=4x+8#

#"subtract y from both sides"#

#cancel(y)cancel(-y)-5=4x-y+8#

#rArr-5=4x-y+8#

#"subtract 8 from both sides"#

#-5-8=4x-ycancel(+8)cancel(-8)#

#rArr4x-y=-13larrcolor(red)"in standard form"#

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