Question

How do you write `y + 5 = -5(x - 3)` in standard form?

Answer 1

`y+5x-10=0`

Explanation:

The equation of a line in `color(blue)"standard form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(ax+by+c=0)color(white)(2/2)|)))`

Arranging the given equation into this form.

distribute the bracket.

`rArry+5=-5x+15`

add 5x to both sides.

`y+5x+5=cancel(-5x)cancel(+5x)+15`

`rArry+5x+5=15`

subtract 15 from both sides.

`y+5x+5-15=cancel(15)cancel(-15)`

`rArry+5x-10=0larrcolor(red)" in standard form"`