How do you write #y-6=-3(x+2)# in standard form?
1 Answer
Mar 24, 2017
Explanation:
The equation of a line in
#color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.
#"Rearrange " y-6=-3(x+2)" into this form"# distribute and simplify.
#rArry-6=-3x-6# add 3x to both sides.
#3x+y-6=cancel(-3x)cancel(+3x)-6#
#rArr3x+y-6=-6# add 6 to both sides.
#3x+ycancel(-6)cancel(+6)=-6+6#
#rArr3x+y=0larrcolor(red)" in standard form"#