# How do you write Y=-7(x-3)^2+12 in standard form?

$y = - 7 \left({x}^{2} - 6 x + 9\right) + 12 = - 7 {x}^{2} + 42 x - 63 + 12$ =
$= - 7 {x}^{2} + 42 x - 51$