How do you write #y+8=-11/12(x-14)# in standard form?

Question

1679 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-02T15:02:53

#y=-11/12x+4 5/6" "->" "y=-11/12x+29/6#

You need #y# on its own on one side of the equals and everything else on the other side.

Subtract 8 from both sides

#y=-11/12(x-14)-8#

Multiply everything inside the brackets by #-11/12#

#y=-11/12x +[(-11/12)xx(-14)]-8#

#y=-11/12x+4 5/6#

#y=-11/12x+29/6#