# How do you write y+8=-11/12(x-14) in standard form?

Apr 2, 2017

$y = - \frac{11}{12} x + 4 \frac{5}{6} \text{ "->" } y = - \frac{11}{12} x + \frac{29}{6}$

#### Explanation:

You need $y$ on its own on one side of the equals and everything else on the other side.

Subtract 8 from both sides

$y = - \frac{11}{12} \left(x - 14\right) - 8$

Multiply everything inside the brackets by $- \frac{11}{12}$

$y = - \frac{11}{12} x + \left[\left(- \frac{11}{12}\right) \times \left(- 14\right)\right] - 8$

$y = - \frac{11}{12} x + 4 \frac{5}{6}$

$y = - \frac{11}{12} x + \frac{29}{6}$