How do you write y + 9 = -3(x - 2)  in standard form?

Nov 19, 2017

$3 x + y = - 3$

Explanation:

$\text{the equation of a line in "color(blue)"standard form }$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{A x + B y = C} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

$\text{where A is a positive integer and B, C are integers}$

$\text{rearrange "y+9=-3(x-2)" into this form}$

$\Rightarrow y + 9 = - 3 x + 6$

$\text{add 3x to both sides}$

$3 x + y + 9 = \cancel{- 3 x} \cancel{+ 3 x} + 6$

$\Rightarrow 3 x + y + 9 = 6$

$\text{subtract 9 from both sides}$

$3 x + y \cancel{+ 9} \cancel{- 9} = 6 - 9$

$\Rightarrow 3 x + y = - 3 \leftarrow \textcolor{red}{\text{in standard form}}$