How do you write #y + 9 = -3(x - 2) # in standard form?
1 Answer
Nov 19, 2017
Explanation:
#"the equation of a line in "color(blue)"standard form "# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
#"where A is a positive integer and B, C are integers"#
#"rearrange "y+9=-3(x-2)" into this form"#
#rArry+9=-3x+6#
#"add 3x to both sides"#
#3x+y+9=cancel(-3x)cancel(+3x)+6#
#rArr3x+y+9=6#
#"subtract 9 from both sides"#
#3x+ycancel(+9)cancel(-9)=6-9#
#rArr3x+y=-3larrcolor(red)"in standard form"#