How do you write $y + 9 = 4 x - 8$ $y + 9= 4x - 8$ in standard form?

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Answer 1 · 2018-06-11T18:27:18

$- 4 x + y = - 17$ $-4x+y=-17$

Standard for is given by

$A x + B y = C$ $Ax+By=C$

We essentially want our constants on the left, and the variables on the right. Let's subtract $4 x$ $4x$ from both sides to get

$- 4 x + y + 9 = - 8$ $-4x+y+9=-8$

Next, let's subtract $9$ $9$ from both sides to get

$- 4 x + y = - 17$ $-4x+y=-17$

We have our variables on one side, and the constants on the other, thus this equation is in standard form.

Hope this helps!

Answer 2 · 2018-06-11T18:34:05

$- 4 x + y = - 17$ $-4x+y=-17$

Standard form uses the equation

$A x + B y = C$ $Ax+By=C$

So really all we have to do is get the $x$ $x$ and $y$ $y$ variable on one side of the equal sign and the regular number on the other side.

First, let’s get the variables together. Subtract $4 x$ $4x$ from both sides:

$y + 9 - 4 x = - 8$ $y+9-4x=-8$

Now, subtract $9$ $9$ from both sides:

$y - 4 x = - 8 - 9$ $y-4x=-8-9$

$y - 4 x = - 17$ $y-4x=-17$

If you want to put it in traditional standard form like below you can, however it does not matter.

$- 4 x + y = - 17$ $-4x+y=-17$

How do you write y+9=4x−8y + 9= 4x - 8 in standard form?