# How do you write y = (x − 1)^2 − 1 in standard form?

Jun 19, 2015

$y = {x}^{2} - 2 x$

#### Explanation:

$y = {\left(x - 1\right)}^{2} - 1$

$= \left(x - 1\right) \left(x - 1\right) - 1$

$= {x}^{2} - 2 x + 1 - 1$

$= {x}^{2} - 2 x$

Standard form places the terms in descending powers of $x$