How do you write $y = (x − 1)^2 − 1$ in standard form?

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Answer 1 · 2015-06-19T18:16:25

$y = x^2-2x$

$y = (x-1)^2 - 1$

$= (x-1)(x-1) - 1$

$= x^2-2x+1-1$

$= x^2-2x$

Standard form places the terms in descending powers of $x$

How do you write y = (x − 1)^2 − 1y = (x − 1)^2 − 1 in standard form?