How do you write #y= x^2-18x+52 into vertex form?

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Answer 1 · 2018-07-02T22:00:57

#(x-9)^2=y+29#

Given equation: #y=x^2-18x+52#

#y=x^2-2(9)x+9^2-9^2+52#

#y=(x-9)^2-81+52#

#y=(x-9)^2-29#

#(x-9)^2=(y+29)#

The above parabola has the vertex at

#(x-9=0, y+29=0)#

#(x=9, y=-29)#

#(9, -29)#