Question

How do you write y=(x-3)^2+5 ?

Answer 1

`y=x^2-6x+14`

Explanation:

Converting the given vertex form to standard form for a quadratic:
`y=(x-3)^(2)+5` (Square the binomial)

`y=x^2-6x+9+5`

`y=x^2-6x+14`