# How do you write y=(x-3)^2+5 ?

Mar 12, 2018

$y = {x}^{2} - 6 x + 14$

#### Explanation:

Converting the given vertex form to standard form for a quadratic:
$y = {\left(x - 3\right)}^{2} + 5$ (Square the binomial)

$y = {x}^{2} - 6 x + 9 + 5$

$y = {x}^{2} - 6 x + 14$