How does $(-13π)/3$ rad =-780°?

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Answer 1 · 2018-04-24T13:35:49

The basic identity is:
$180^circ-=pi$

So, whatever you do to $pi$ you do to $180^circ$

Therefore, to go from radians to degrees, you multiply by $180/pi$

$-(13pi^c)/3*180/pi-=-780^circ$

How does (-13π)/3(-13π)/3 rad =-780°?