# How does the electric force between two charged objects change?

Inverse square variation, $F \setminus \propto \setminus \frac{1}{{D}^{2}}$

#### Explanation:

Electrostatic force between two point charges ${Q}_{1}$ & ${Q}_{2}$ separated by a distance $D$ is given as folows

$F = \setminus \frac{1}{4 \setminus \pi \setminus {\epsilon}_{0}} \setminus \frac{{Q}_{1} {Q}_{2}}{{D}^{2}}$

$F \setminus \propto \setminus \frac{1}{{D}^{2}}$

hence the electrostatic force between two point is inversely proportional to the square of distance between the charges