How does the graph f(x) - g(x) look like? Full question in the description box below.

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1 Answer
Jan 9, 2018

See the explanation

Explanation:

Firstly the question uses the word 'sketch'. So what you draw does not have to be precise.

Let a sketched point be P_aPa

Suppose we have: y_1=f(x_1) and y_2=g(x_1)y1=f(x1)andy2=g(x1)

So P_1->f(x_1)-g(x_1)color(white)("ddd")->color(white)("ddd") (x_1,color(white)("d")y_1-y_2)P1f(x1)g(x1)dddddd(x1,dy1y2)

Draw (lightly) a series of lines parallel to the y-axis. Where each line crosses the plots project a line parallel to the x-axis such that it meets the y-axis and approximate the value of the relevant y's->y_1 and y_2

Then we have y_("sketch")=[y_1=f(x)]-[y_2=g(x)] Mark that point. When you have a number of these points sketch a plot through them. I would suggest a coloured pencil.

Looking at your diagram I notice that we have two labelled points that have the same x-value.

g(x)->(-1,0) and f(x)->(-1,2)

So for this vertical line we have f(x)-g(x)-> (x,y)=(-1, color(white)("d")2-0)=(-1,2)

I also notice that both plots have a shared point (both pass through it) at P_2->(x,y)=(0,1) They also have another shared point (P_3)that is not labelled. You must make sure your plot passes through each of P_1,P_2 and P_3