# How fast will an object with a mass of 16 kg accelerate if a force of 440 N is constantly applied to it?

Use $F = m \times a$ and remember that $1 N = 1 k g \cdot m / {s}^{2}$
$440 \left(N\right) = 16 \left(k g\right) \times a \left(m / {s}^{2}\right)$
Divide by $16 k g$
$a = \frac{440 \cancel{k g} \cdot m / {s}^{2}}{16 \cancel{k g}} = 27.5 m / {s}^{2}$