How fast will an object with a mass of 7 kg accelerate if a force of 38 N is constantly applied to it?

Dec 27, 2015

The acceleration is $\approx \text{5 m/s"^2}$.

Explanation:

From Newton's second law, we have the equation $F = m a$, where, in SI units, $F$ is the force in Newtons, or $\text{kg·m/s"^2}$, $m$ is mass in kg, and $a$ is acceleration in $\text{m/s"^2}$.

Given
$F = \text{38 N"="38 kg·m/s"^2}$
$m = \text{7 kg}$

Unknown
$a$

Solution
Rearrange the equation to isolate $a$ and solve.

$F = m a$

$a = \frac{F}{m}$

$a = \left(38 \text{N")/(7"kg}\right)$

a=(38cancel"kg"·"m/s"^2)/(7cancel"kg")="5.4 m/s"^2$\approx$$\text{5 m/s"^2}$ (rounded to one significant figures)