# How heavy will 6.14 * 10^25 atoms of gold be?

Dec 7, 2015

$20.1$ $k g$
weight of $197$ $N$
This question requires you to use Avogadro's number to convert the atoms to moles, and then use the molar mass of gold ($197 g$/$\text{mol}$) to convert moles to grams.
I'm assuming by "how heavy" you mean mass, but if you wanted to calculate weight you would need to calculate a force by using $F = m a$ where $F$ is the force is the weight in Newton, $m$ is the mass, and $a$ is the acceleration is gravity at Earth's surface ($9.8 m$/${s}^{2}$)