How in the world do I write these expressions for Kc?

I do not see a way to further cancel anything else out?
Please help and explain well per reaction so that I can understand. Sincerely, Ozzy

(1.) #"N"_2(g)+3"H"_2(g) ⇌ 2 "NH"_3(g)#

(2.) #"NO"_2(g) + "NO"_3(g) ⇌ "N"_2"O"_5(g)#

Sincerely, Ozzy

1 Answer
1s2s2p
Feb 20, 2018

  1. #K_c=(["NH"_3]^2)/(["N"_2]["H"_2]^3)#

  2. #K_c=(["N"_2"O"_5])/(["NO"_2]["NO"_3])#

Explanation:

Your reactions are in the form of #"aA"+"bB"rightleftharpoons"cC"# where the lower case letters represent the number of moles while the upper case letters represent the compounds.

As all three compounds are not solids we can include all oh them in the equation:
#K_c=(["C"]^"c")/(["A"]^"a"["B"]^"b")#

  1. #K_c=(["C"]^2)/(["A"]^1["B"]^3)#

#K_c=(["C"]^2)/(["A"]["B"]^3)#

#K_c=(["NH"_3]^2)/(["N"_2]["H"_2]^3)#
#color(white)(l)#
2. #K_c=(["C"]^1)/(["A"]^1["B"]^1)#

#K_c=(["C"])/(["A"]["B"])#

#K_c=(["N"_2"O"_5])/(["NO"_2]["NO"_3])#

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