How is the function 1/9*x^3 +5, x<-319x3+5,x<3 not continuous at x=1 and what type of correspondence does it display?

1 Answer
Jan 9, 2018

Please see below.

Explanation:

For f(x) = 1/9x^3+5f(x)=19x3+5, for x < -3x<3, the domain is (-oo,-3)(,3)

Therefore ff is not defined at x-1x1 so it cannot be continuous there.

Since f'(x) = 1/3 x^2 is always positive, the function is a one to one correspondence.