Question

How is the unit for surface heat capacity derived?

Answer 1

C

Explanation:

Units for heat capacity are Joule per kelvin: `Jcdot K^-1`
`:.`Units for Surface heat capacity would be

Joule per meter square per kelvin: `Jcdot m^-2cdot K^-1`

Now Joule `J` can be written in terms of kg as `kg·m^2·s^-2`

Combining above two we get `(kg·m^2·s^-2)cdot m^-2cdot K^-1`

`:.`unit for surface heat capacity are `kg·s^-2cdot K^-1`