# How man kL are in 297 L?

There are $0.297 \cdot k L$
The prefix $k$ means ${10}^{3}$, and thus there are ${10}^{-} 3 \cdot k L \cdot {L}^{-} 1$.....
and so $297 \cdot \cancel{L} \times {10}^{-} 3 \cdot k L \cdot \cancel{{L}^{-} 1} = 297 \times {10}^{-} 3 \cdot k L$
$= 0.297 \cdot k L$