How many atoms are contained in 0.55 moles of Br?

1 Answer
Apr 12, 2017

Answer:

#0.55xxN_A# #"bromine atoms.........."#

Explanation:

Where #N_A="Avogadro's Number,"# #6.022xx10^23*mol^-1#.

And thus, #0.55*cancel(mol)xx6.022xx10^23*cancel(mol^-1)=3.31xx10^23# #"bromine ATOMS"#.

Note that here we use the mole as would use any other collective term, i.e. dozen, score, gross............Of course the mole specifies a much larger quantity of stuff.

Also note that we specify a quantity of #0.55# #mol# #"bromine atoms"#. A quantity of #0.55# #mol# #"bromine molecules"# would contain TWICE this number of bromine atoms. Why?