# How many atoms are in 0.0362 mol K?

There are approx $\cong 2.2 \times {10}^{22}$ individual potassium atoms.
In $\text{1 mole}$ there are $6.022 \times {10}^{23}$ particles.
Thus in $0.0362 \cdot m o l$ potassium metal, there are $0.0362 \cdot m o l \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$ individual potassium atoms $\cong 2.2 \times {10}^{22}$ such atoms. What is the mass of this quantity?