# How many atoms are in 0.075 mol of titanium?

Mar 19, 2016

There are $0.075 \times {N}_{A}$ $\text{titanium atoms}$, where ${N}_{A}$ $=$ $\text{Avogadro's number}$ $=$ $6.02243 \times {10}^{23}$.

#### Explanation:

If I were to ask you how many eggs are in a half dozen, I think you would immediately answer "6". In effect, you have asked the same thing.

In one mole of stuff (atoms, molecules, eggses), there are $6.02243 \times {10}^{23}$ individual items of that stuff. $6.02243 \times {10}^{23}$ individual ""^1H atoms have a mass of $1$ $g$ precisely. This is why we use the number. If I measure out a gram or so of stuff on the benchtop, I know precisely the number of individual atoms and molecules that constitute that stuff.

$\text{Avogadro's number}$ is thus the link between the micro world of atoms and molecules, about which we can only conceive, with the macro world of grams, and kilograms, and litres, that we can measure practically.

Back to your question. If there are ${N}_{A}$, 1 mole of titanium atoms, there is a mass of $47.87$ $g$ (from where did I get that mass?). What is the mass of $0.075$ $m o l$ of titanium metal?