# How many atoms are in 1.4 mol of phosphorous trifluoride (PF_3)?

Apr 15, 2016

$4 \times 1.4 \times {N}_{A}$, where ${N}_{A} = \text{Avogadro's Number}$
${N}_{A} = \text{Avogadro's Number}$ $=$ $6.02214 \times {10}^{23}$. $1$ $m o l$ of stuff contains this many particles of stuff.
Since there are 4 atomic particles in $P {F}_{3}$, $1.4$ is multiplied by $4$, and then by ${N}_{A}$ to give the total number of atoms/particles.
So, how many phosphorus atoms in $1.4$ $m o l$ $P {F}_{3}$; how many fluorine atoms?