# How many atoms are in 1.54 moles of Bromine (Br)?

And thus in 1.54 moles of bromine, there are $2 \times 1.54 \cdot m o l \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1 \cong 18 \times {10}^{23}$ $\text{bromine atoms}$.