How many atoms are in 15.0 of silver?

1 Answer
Dr. Hayek
Apr 14, 2016

#8.37xx10^(22)" atoms " Ag#

Explanation:

Assuming you mean 15.0g, then, to calculate the number of atoms, you write:

#?Ag " atoms"=15.0 cancel(g Ag)xx(1cancel(mol Ag))/(107.87 cancel(g Ag))xx(6.022xx10^(23)"atoms")/(1cancel(mol Ag))=8.37xx10^(22)" atoms " Ag#.

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