# How many atoms are in 2.00 moles of NO_2?

There are $6 \times 6.022 \times {10}^{23}$ atoms in $2.00 \cdot m o l$ $N {O}_{2} \left(g\right)$.
In the one mole of $N {O}_{2}$, there are $\text{Avogadro's number}$ of $N {O}_{2}$ molecules; i.e. ${N}_{A}$ $N {O}_{2}$ molecules.
And thus in $2.00 \cdot m o l$ of $N {O}_{2}$ there are $6 \times {N}_{A}$ nitrogen and oxygen atoms. In terms of ${N}_{A}$, how many oxygen atoms, and how many nitrogen atoms in this quantity?