How many atoms are in 33 g of titanium (Ti)?

1 Answer
anor277
Apr 8, 2017

Approx. #4xx10^23# individual titanium atoms..........

Explanation:

We work out the molar quantity of titanium metal:

#"Moles of titanium"# #=# #(33*g)/(47.9*g*mol^-1)~=0.70*mol#

Note that this quotient is dimensionally consistent. We wanted an answer in #"moles"#, we got the quotient with units of:

#cancelg/(cancelg*mol^-1)=1/(mol^-1)=1/(1/(mol))=mol# as required...... Capisce?

And then we multiply this molar quantity by #"Avogadro's number"#, which is #6.022xx10^23*mol^-1# (and the number of titanium atoms has a mass of #47.9*g# by definition).

#"Number of titanium atoms"=6.022xx10^23*mol^-1xx0.7*mol#

#~=4.0xx10^23#

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