# How many atoms are in 5.00 moles of copper?

$5 \times {N}_{A}$, where ${N}_{A}$ $=$ $\text{Avogadro's number}$
$\text{Avogadro's number}$ $=$ $6.022 \times {10}^{23}$. It has the property that ${N}_{A}$ copper atoms, have a MASS of $63.55$ $g$.
What is the mass of $5 \times {N}_{A} \text{ copper atoms}$?