How many atoms are in 7.10 g of chlorine atoms?

$\left[7.10 \cancel{g C l}\right] \left[\cancel{1 \text{mol Cl")/(35.4527cancel"g Cl")][(6.02*10^23 "atoms Cl")/cancel(1"mol Cl}}\right]$
$\approx 1.21 \cdot {10}^{23}$ atoms of chlorine