How many atoms are in 931.6 g #KMnO_4#?

1 Answer
anor277
Mar 3, 2016

Quite a few: each formula unit of potassium permanganate contributes 6 atoms.

Explanation:

Molar quantity of #KMnO_4# #=# #(931.6*g)/(158.034*g*mol^-1)# #=# #5.89*mol#.

There are thus #5.89# #mol# #xx# #N_A# #xx# #"6 atoms" # #=# #35.37*mol# #xx# #N_A" atoms"# #=# #??#

#N_A = "Avogadro's number", 6.022xx10^23*mol^-1#

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