# How many atoms are present in 1.55 mol of sodium?

$9.33 \cdot {10}^{23}$ atoms of $N a$
To find the amount of atoms (or molecules) of any element, we multiply the number of mols of element with Avogadro's Number, $6.022 \cdot {10}^{23}$
$1.55 m o l$ $N a$ $\frac{6.022 \cdot {10}^{23}}{1 m o l}$ = $9.33 \cdot {10}^{23}$ atoms of $N a$