# How many atoms are present in 4.00 mol of aluminum?

To determine the amount of atoms (or molecules) present given the moles of an element, you multiply the amount of moles by Avogadro's number, $6.022 \cdot {10}^{23}$
4 mol $A l$ $\frac{6.022 \cdot {10}^{23}}{1 m o l}$= $2.41 \cdot {10}^{24}$ atoms/molecules of $A l$