How many atoms are present in 95.1 L #H_2O# at STP?

1 Answer
anor277
Feb 6, 2016

You should tell us. What is the state of water at STP?

Explanation:

There are 95.1 kg of water at STP; i.e #(95.1xx10^3*g)/(18.01*g*mol^-1)# #=# #??# #"moles"#.

Now the mole represents Avogadro's number of particles, #6.022xx10^23# #mol^-1#, #N_A#. So multiply the number of moles first by #N_A# to give the number water molecules, and then mulitply this quantity by #3#. Why three?

Because this is a large number, you would be justified in using the symbol #N_A# in your answer, provided you defined it.

Related questions
See all questions in The Mole
Impact of this question
1336 views around the world
You can reuse this answer
Creative Commons License