# How many atoms of neon gas would a container with a volume of 67.2 L hold at STP?

May 9, 2016

The molar volume of an Ideal Gas at $S T P$ is $22.4 \cdot L$.

#### Explanation:

So all we have do is divide the actual volume by the molar volume, and mulitply that number by ${N}_{A} \text{, Avogadro's number}$, which is the number of particles in one mole of particles:

Thus:

$\text{Number of atoms " =" } \frac{67.2 \cdot L}{22.4 \cdot L \cdot m o {l}^{-} 1} \times {N}_{A}$

$= \frac{67.2 \cdot L}{22.4 \cdot L \cdot m o {l}^{-} 1} \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$

$= 3 \times {N}_{A}$ neon atoms. Neon, as a Noble gas, is an atomic species, though here the atoms are gaseous and not associated.