# How many chloride ions are there in 4.50 mol of aluminum chloride?

##### 1 Answer
Jun 14, 2016

1 mol aluminium chloride $A l C {l}_{3}$ delivers 3 mol of $C {l}^{-}$ ions.

#### Explanation:

So $4.50$ mol $A l C {l}_{3} \leftrightarrow 3 \times 4.50 = 13.50$ mol $C {l}^{-}$

1 mol contains $\approx 6.02 \times {10}^{23}$ particles, so the answer is:

${n}_{C {l}^{-}} = 13.50 \times 6.02 \times {10}^{23} = 81.27 \times {10}^{23} \approx 8.13 \times {10}^{24}$

(rounded to 3 significant digit because of the $4.50$)