How many formula units are contained in 1.34g #CaO#?

1 Answer
anor277
Mar 7, 2016

#(1.34*g)/(74.10*g*mol^-1)# #xx# #N_A#, where #N_A# #=# #"Avogadro's number"#

Explanation:

There are #(1.34*g)/(74.10*g*mol^-1)# #=# #?? " moles calcium hydride"#.

Now, it is a fact that #1# #"mole"# of stuff, there are #6.022xx10^23# individual items of that stuff.

You have #0.0181# #mol#. Therefore:

#0.0181# #mol# #xx# #6.022xx10^23*mol^-1# #=# #??" formula units of calcium hydroxide"#.

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