# How many formula units make up 16.2 g of magnesium chloride?

$\text{No. of formula units}$ $\equiv$ $\frac{16.2 \cdot g}{95.21 \cdot g \cdot m o {l}^{-} 1} \times {N}_{A} \ldots \ldots .$
$\ldots \text{where "N_A="Avogadro's number} , 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.