# How many grams are contained in 2.22 moles of sucrose C_12H_22O_11?

$759 g$ of ${C}_{12} {H}_{22} {O}_{11}$.
The relationship between the number of mole ($n$) and the mass ($m$) of sucrose is the following:
$n = \frac{m}{M M}$, where $M M = 342 \frac{g}{m o l}$ is the molar mass of sucrose.
$\implies m = n \times M M = 2.22 \cancel{m o l} \times 342 \frac{g}{\cancel{m o l}} = 759 g$