# How many grams are in 1.25 x 10^22 atoms of oxygen?

Apr 7, 2017

Approx. $0.3 \cdot g$........

#### Explanation:

I know that $6.022 \times {10}^{23}$ $\text{oxygen atoms}$ have a mass of $16.00 \cdot g$. How do I know this? Well $6.022 \times {10}^{23}$ $\text{oxygen atoms}$ specifies a $\text{mole}$ of oxygen atoms, and these molar masses are listed and specified on the Periodic Table.

And thus mass............

$= \left(1.25 \times {10}^{22} \cdot \text{oxygen atoms")/(6.022xx10^23*"oxygen atoms} \cdot m o {l}^{-} 1\right) \times 16.00 \cdot g \cdot m o {l}^{-} 1$

$\cong 0.3 \cdot g$