How many grams are in 4.1 moles of #CO_2#?

1 Answer
Jan 20, 2016

#m=180.4g#

Explanation:

The relationship between the mass and number of mole is giving by:

#n=m/(MM)#

where, #n# is the number of mole
#m# is the mass of the compound
and #MM# is the molar mass

#=>m=nxxMM=4.1cancel(mol)xx44g/(cancel(mol))=180.4g#