How many grams are in 4.1 moles of CO_2?

Jan 20, 2016

$m = 180.4 g$

Explanation:

The relationship between the mass and number of mole is giving by:

$n = \frac{m}{M M}$

where, $n$ is the number of mole
$m$ is the mass of the compound
and $M M$ is the molar mass

$\implies m = n \times M M = 4.1 \cancel{m o l} \times 44 \frac{g}{\cancel{m o l}} = 180.4 g$