How many grams are in 4.5 x 1028 moles of sodium fluoride, NaF?

1 Answer
Feb 20, 2018

Answer:

I get around #3139542 \ "g"#.

Explanation:

I think your question is,

How many grams are in #4.5 xx 10^28# molecules of sodium fluoride, #NaF#?

That's because if you talk about #4.5 x 1028# moles of sodium fluoride, you would get a really absurd number of grams.

So, I'd solve your problem assuming your question is How many grams are in #4.5 xx 10^28# molecules of sodium fluoride, #NaF#?.

In that, we first have to convert the amount of molecules into moles.

We know that #1 \ "mol" = 6.02*10^23# molecules, so in here, we get

#(4.5*10^28cancel"molecules")/(6.02*10^23cancel"molecules""/mol")=74750.8306~~74751 \ "mol"#

Sodium fluoride has a molar mass of #42 \ "g/mol"#. So, the mass of #74751# moles of sodium fluoride will be

#42"g/"cancel"mol"*74751cancel"mol"=3139542 \ "g"#