Question

How many grams are in 4.5 x 1028 moles of sodium fluoride, NaF?

Answer 1

I get around `3139542 \ "g"`.

Explanation:

I think your question is,

How many grams are in `4.5 xx 10^28` molecules of sodium fluoride, `NaF`?

That's because if you talk about `4.5 x 1028` moles of sodium fluoride, you would get a really absurd number of grams.

So, I'd solve your problem assuming your question is How many grams are in `4.5 xx 10^28` molecules of sodium fluoride, `NaF`?.

In that, we first have to convert the amount of molecules into moles.

We know that `1 \ "mol" = 6.02*10^23` molecules, so in here, we get

`(4.5*10^28cancel"molecules")/(6.02*10^23cancel"molecules""/mol")=74750.8306~~74751 \ "mol"`

Sodium fluoride has a molar mass of `42 \ "g/mol"`. So, the mass of `74751` moles of sodium fluoride will be

`42"g/"cancel"mol"*74751cancel"mol"=3139542 \ "g"`