# How many grams are in 5.66 mol of CaCO_3?

Molar mass of calcium carbonate is $100.1$ $g \cdot m o {l}^{- 1}$. There are 5.66 mol. So..............
$5.66$ $\cancel{m o l}$ $\times$ $100.1$ $g \cdot \cancel{m o {l}^{-} 1}$ $=$ ??g