How many grams are there in #4.5 * 10^22# formula units of #Ba(NO_2)_2#?

1 Answer
anor277
May 22, 2016

Well, if there are #6.022xx10^23# #Ba(NO_2)_2# formula units there are #229.34*g# by definition.

Explanation:

The molar mass of #Ba(NO_2)_2# is #229.34*g*mol^-1#.

To get the mass of the given quantity, all we have do is divide this quantity by #"Avogadro's number"#, and then multiply by the molar mass.

#(4.5xx10^22)/(6.022xx10^23*mol^-1)# #xx229.34*g*mol^-1# #=# #??g#

Related questions
See all questions in The Mole
Impact of this question
11571 views around the world
You can reuse this answer
Creative Commons License