Question

How many grams of AgCl are needed to make a 2m solution?

Answer 1

Molality = (Number of moles of solute)/(Mass of solvent in `kg`)

Explanation:

In the given question for `AgCl` solution ;

THEORETICALLY :-

molality `= 2m`

`rArr 2m=`(Moles of `AgCl`)/(Mass of `H_2O` in `kg`)

`rArr` Moles of `AgCl` `= 2mxx`(Mass of `H_2O` in `kg`)

`rArr` Moles of `AgCl` `= 2mxx`(Mass of `H_2O` in `g`)`xx1000`

We know that the Molecular weight of `AgCl` is `143.32 g` :-

`:.` The amount (grams) of `AgCl` needed

`=`Moles of `AgClxx143.32 g`

`= {2mxx`(Mass of `H_2O` in `g`)`xx1000`}`xx143.32 g`

NOTE : Actually (EXPERIMENTALLY)this is NOT possible because `AgCl` is insoluble in Water.

Hope is helps :)