# How many grams of Al are in 4.70 moles?

1 mole of aluminum atoms has a mass of $26.98$ $g$. You have $4.70$ moles.
1 mole of atoms represents Avogadro's number, i.e. $6.022 \times {10}^{23}$. This is simply a number like 10 or 12, or 20 or 100. If there are are $6.022 \times {10}^{23}$ aluminum atoms there is a MASS of $26.98$ $g$. So if you have 4.70 moles, there is a mass of approx. $127$ $g$ of aluminum.