How many grams of calcium nitrate are needed to make 3.30 L of a .10 M solution?

1 Answer
Junaid Mirza
Apr 7, 2018

#"21.1 g"#

Explanation:

#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#

#"0.10 M" = "n"/"3.30 L"#

#"n = 0.10 M × 3.30 L = 0.33 mol"#

Molar mass of calcium nitrate #("Ca(NO"_3")"_2) = "164.088 g/mol"#

Mass of #"0.33 mol"# of #"Ca(NO"_3")"_2# is

#0.33 cancel"mol" × 164.088\ "g"/cancel"mol" = "21.1 g"#

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